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TNPSC Civil Engineering (Code: 443): Answer key

TNPSC Civil Engineering (Code 443): Answer key

1. The angle of twist is ______ to twisting moment.

A. Inversely proportional

B. Equal

C. Directly proportional

D. Greater than (or) equal to

Explanation: According to the torsion equation, the angle of twist is directly proportional to the twisting moment (Torque). The torsion formula is given by: $T/J = G\theta/L = \tau/R$. Here, $\theta$ (angle of twist) is directly proportional to T (twisting moment).
2. Maximum bending moment in a cantilever beam is $4\times10^{6}Nmm$, its section modulus is $4000~mm^{3}$ its maximum bending stress is equal to ______

A. $4000~N/mm^{2}$

B. $10,000~N/mm^{2}$

C. $1000~N/mm^{2}$

D. $40,000~N/mm^{2}$

Explanation: The relationship between bending stress ($\sigma$), bending moment (M), and section modulus (Z) is given by the bending equation: $M/I = \sigma/y$, or $\sigma = M/Z$. Given $M = 4\times10^{6}~Nmm$ and $Z = 4000~mm^{3}$, the maximum bending stress is $\sigma_{max} = M/Z = (4\times10^{6}) / 4000 = 1000~N/mm^{2}$.
3. The torque transmitted by a hollow shaft is given by the relation, _______

A. T = $\tau\times\frac{\pi}{16}[\frac{D^{4}-d^{4}}{D}]$

B. T = $\tau\times\frac{\pi}{32}[\frac{D^{4}-d^{4}}{D}]$

C. T = $\tau\times\frac{\pi}{16}[\frac{D^{3}-d^{3}}{D}]$

D. T = $\tau\times\frac{\pi}{32}[\frac{D^{3}-d^{3}}{D}]$

Explanation: The torsion equation for a hollow shaft is given by $T/J = \tau/R$, where $J$ is the polar moment of inertia and $R$ is the outer radius. For a hollow circular section, $J = \frac{\pi}{32}(D^4 - d^4)$ and $R = D/2$. Substituting these values into the torsion equation: $T = \tau \times (J/R) = \tau \times \frac{(\pi/32)(D^4-d^4)}{D/2} = \tau \times \frac{\pi}{16}[\frac{D^{4}-d^{4}}{D}]$.
4. A frame in which the number of members is more than $(2j-3)$ is known as ______

A. Perfect frame

B. Deficient frame

C. Redundant frame

D. Cantilever frame

Explanation: A perfect frame is one that satisfies the condition $m = 2j - 3$. A deficient frame has $m < 2j - 3$, and a redundant frame has $m > 2j - 3$, where 'm' is the number of members and 'j' is the number of joints.
5. A solid circular shaft of length 2 m and diameter 0.02 m is made of steel with shear modulus 80 GPa. Calculate polar moment of inertia of the shaft.

A. $5\times10^{-8}m^{4}$

B. $0.5\pi\times10^{-8}m^{4}$

C. $0.5\times10^{-8}m^{4}$

D. $5\pi\times10^{-8}m^{4}$

Explanation: The formula for the polar moment of inertia (J) of a solid circular shaft is $J = \frac{\pi}{32}d^4$. Given diameter, $d = 0.02~m$. $J = \frac{\pi}{32}(0.02)^4 = \frac{\pi}{32}(16\times10^{-8}) = \frac{\pi}{2}\times10^{-8} = 0.5\pi\times10^{-8}~m^{4}$.
6. Moment of resistance of the section 'M' is equal to ______

A. $M = \frac{\sigma}{Z}$

B. $M = \sigma\times Z$

C. $M = \sigma+Z$

D. $M = \sigma-Z$

Explanation: The bending equation is $\frac{M}{I} = \frac{\sigma}{y}$. Rearranging gives $M = \sigma \times \frac{I}{y}$. Since the section modulus is $Z = \frac{I}{y}$, the moment of resistance (M) is equal to the product of bending stress ($\sigma$) and section modulus (Z), i.e., $M = \sigma \times Z$.
7. Section modulus of a solid circular section is given by ______ (where, $d=$ diameter)

A. $\frac{\pi d^{3}}{64}$

B. $\frac{\pi d^{3}}{32}$

C. $\frac{\pi d^{4}}{64}$

D. $\frac{\pi d^{2}}{16}$

Explanation: The section modulus (Z) is defined as the ratio of the moment of inertia (I) to the distance of the outermost fiber from the neutral axis (y). For a solid circular section, $I = \frac{\pi d^4}{64}$ and $y = d/2$. Therefore, $Z = \frac{I}{y} = \frac{\pi d^4/64}{d/2} = \frac{\pi d^3}{32}$.
8. A steel wire of 10 mm diameter is bent into a circular shape of 5 m radius. $E=2\times10^{5}\frac{N}{mm^{2}}$. The maximum bending stress induced in the wire is ______

A. $20~N/mm^{2}$

B. 200 MPa

C. 20 kPa

D. 200 GPa

Explanation: The maximum bending stress ($\sigma$) is calculated using the bending equation: $\frac{\sigma}{y} = \frac{E}{R}$. We are given: $y = d/2 = 10/2 = 5~mm$, $E = 2\times10^5~N/mm^2$, and $R = 5~m = 5000~mm$. Therefore, $\sigma = \frac{E \times y}{R} = \frac{2\times10^5 \times 5}{5000} = 200~N/mm^2$. Since $1~MPa = 1~N/mm^2$, the stress is 200 MPa.
9. If hollow circular section has outer diameter 'D' and inner diameter 'd'. What is the value of Moment of Inertia?

A. $\pi/{64}(D^{4}-d^{4})$

B. $\pi/{64}(D^{3}-d^{3})$

C. $\pi/{4}(D^{4}-d^{4})$

D. $\pi/{4}(D^{3}-d^{3})$

Explanation: The moment of inertia (I) for a hollow circular section about its neutral axis is given by $I = \frac{\pi}{64}(D^4-d^4)$, where D is the outer diameter and d is the inner diameter.
10. A hollow shaft of same cross-sectional area as compared to a solid shaft will transmit?

A. same torque

B. less torque

C. more torque

D. unpredictable

Explanation: For the same cross-sectional area, a hollow shaft has a larger polar moment of inertia compared to a solid shaft. Since torque transmitted is directly proportional to the polar moment of inertia, a hollow shaft can transmit more torque than a solid shaft of the same material and cross-sectional area.
11. In simply supported beams, shear force is maximum at _______

A. The center

B. The centroid of the beam

C. The supports

D. The point of zero BM

Explanation: For a simply supported beam with a uniformly distributed load or a central point load, the maximum shear force occurs at the supports.
12. Match the following:

A. A-2 B-3 C-4 D-1

B. A-4 B-3 C-2 D-1

C. A-3 B-4 C-1 D-2

D. A-4 B-1 C-2 D-3

13. The maximum shear force in the beam will be ______

A. W

B. 2W

C. 4W

D. Zero

14. The deformation per unit length is called ______

A. strain

B. tensile stress

C. compressive stress

D. shear stress

Explanation: Strain is the measure of the deformation of a body under load. It is defined as the change in dimension per unit of original dimension. For tensile or compressive loads, it is the change in length per unit length.
15. The total change in length of a bar of different sections is equal to the ______

A. sum of changes in the length of different sections

B. average of changes in the lengths of different sections

C. difference of changes in the lengths of sections

D. sum of changes in the half length of different sections

Explanation: When a bar is composed of different sections subjected to the same axial load, the total elongation or change in length is the algebraic sum of the changes in length of each individual section. This is a fundamental principle of mechanics.
16. An elastic bar of cross sectional area $400~mm^{2}$ carries an axial tensile load of 600 kN, the stress on the bar is equal to ______

A. $6000~N/mm^{2}$

B. $4000~N/mm^{2}$

C. $1500~N/mm^{2}$

D. $2500~N/mm^{2}$

Explanation: Stress ($\sigma$) is calculated as force (P) per unit area (A), i.e., $\sigma = P/A$. Given: $P = 600~kN = 600\times10^3~N$ and $A = 400~mm^2$. So, $\sigma = \frac{600\times10^3}{400} = 1500~N/mm^{2}$.
17. Within elastic limit in a loaded member of material, stress is _______ to strain.

A. inversely proportional

B. directly proportional

C. independent of

D. equal to

Explanation: According to Hooke's Law, within the elastic limit, the stress in a material is directly proportional to the strain produced. This relationship is a fundamental concept in the study of material properties.
18. If 'l' and '$\delta l$' are the length and change in length respectively, the strain is equal to ______

A. $l /\delta l$

B. $\delta l/l$

C. $l \times \delta l$

D. $\delta l^{2}$

Explanation: Strain ($\epsilon$) is defined as the ratio of the change in length to the original length. Therefore, $\epsilon = \frac{\delta l}{l}$.
19. The internal resistance which the body offers to meet the load or external force is called _______

A. Pressure

B. Strain

C. Stress

D. Young's modulus

Explanation: Stress is the internal resistance or resisting force per unit area that a body offers to an externally applied load. It is an internal property of the material.
20. The ratio of shear stress to the corresponding shear strain within the elastic limit is known as ______

A. Modulus of elasticity

B. Modulus of rigidity

C. Bulk modulus

D. Poisson's ratio

Explanation: The Modulus of Rigidity (G), also known as the Shear Modulus, is the ratio of shear stress ($\tau$) to shear strain ($\gamma$) within the proportional limit. It is a measure of a material's resistance to shear deformation.
21. When a steel member is subjected to tension, the area of cross section continuously change due to

A. the poisson effect

B. the longitudinal strain

C. the shear

D. the bending moment

Explanation: When a material is subjected to axial tension, it elongates in the direction of the force and simultaneously contracts laterally. This phenomenon, known as the Poisson effect, causes a continuous change in the cross-sectional area.
22. The ratio of a effective length to corresponding radius of gyration is

A. Slenderness ratio

B. Moment of inertia

C. Design value

D. Buckling stress

Explanation: The slenderness ratio is defined as the ratio of the effective length of a column to its least radius of gyration. It is a crucial parameter in determining the buckling behaviour of compression members.
23. Web crippling generally occurs at the point where

A. Bending moment is maximum

B. Shear force is minimum

C. Deflection is maximum

D. Concentrated loads act

Explanation: Web crippling is a type of failure in beams where the web buckles under a concentrated load or at a support. This type of failure is localised and occurs due to high compressive stresses under the load.
24. In rolled steel beams, shear force is mostly resisted by

A. Web only

B. Flange only

C. Web and flange together

D. Thickness and flange

Explanation: For I-sections, the web is thin but deep, and it resists most of the shear force. The flanges, being far from the neutral axis, primarily resist the bending moment.
25. As per IS 800-2007, the effective slenderness ratio $(\frac{KL}{r})_{e}$ of battened columns, shall be taken as how much times of $(\frac{KL}{r})_{o}$ (The maximum actual slenderness ratio of the column)?

A. 1

B. 1.05

C. 1.08

D. 1.1

Explanation: As per IS 800-2007, Clause 7.6.6.1, the effective slenderness ratio of a battened column is to be increased by 10% to account for shear deformation. Therefore, the effective slenderness ratio, $(\frac{KL}{r})_{e}$, is taken as 1.1 times the maximum actual slenderness ratio.
26. The minimum thickness at the edge of the footing that rests on soils shall be

A. 150 mm

B. 125 mm

C. 100 mm

D. 75 mm

Explanation: As per IS 456-2000, Clause 34.1.2, the minimum thickness of a reinforced concrete footing on soil at its edge shall not be less than 150 mm.
27. Which of the following statements are true about design of compression member?
(i) Slenderness ratio should be minimum
(ii) Slenderness ratio should be large
(iii) Radius of gyration should be large

A. (i) only

B. (iii) only

C. (ii) and (iii) only

D. (i) and (iii) only

Explanation: For the design of a compression member, the slenderness ratio (L_eff/r) should be as low as possible to prevent buckling. A larger radius of gyration (r) leads to a lower slenderness ratio, making the column more stable and increasing its load-carrying capacity. Hence, both statements (i) and (iii) are true.
28. The effective length of the column with one end fixed and the other end hinged shall be

A. $1.0 l$

B. $2l$

C. $l/2$

D. $l/\sqrt{2}$

Explanation: As per IS 456, for a column with one end fixed and the other hinged, the effective length is $L_{eff} = L/\sqrt{2} = 0.707L$. The question provides a different set of options; however, if $1.0/\sqrt{2}$ is intended, that would be the closest. The options are $1.0l$, $2l$, $l/2$, and $l/\sqrt{2}$. The correct one is $l/\sqrt{2}$ or $0.707l$.
29. The minimum eccentricity to be considered for an axially loaded circular column of diameter 300 mm with unsupported length of 6 m is

A. 20 mm

B. 21 mm

C. 25 mm

D. 22 mm

Explanation: According to IS 456-2000, Clause 25.4, the minimum eccentricity ($e_{min}$) is given by $e_{min} = \frac{L}{500} + \frac{D}{30}$, but not less than 20 mm. Given: Unsupported length, L = 6 m = 6000 mm; Diameter, D = 300 mm. $e_{min} = \frac{6000}{500} + \frac{300}{30} = 12 + 10 = 22~mm$. Since this value is greater than 20 mm, the minimum eccentricity is 22 mm.
30. Which of the following statement is true about design of footing?
(i) The minimum cover to reinforcement is 50 mm under normal condition
(ii) The minimum cover to reinforcement is 75 mm under exposure condition
(iii) Minimum reinforcement of footing is 0.002% of width of footing

A. (i) only

B. (ii) only

C. (i) and (ii) only

D. (iii) and (i) only

Explanation: Based on IS 456-2000, Clause 26.4.2.2, the minimum cover for footings is 50 mm. Statement (i) is correct. Statement (ii) is incorrect, as the minimum cover for exposure conditions is not specified as 75 mm in IS 456-2000. Statement (iii) is incorrect; the minimum reinforcement in footings is a percentage of the gross cross-sectional area, not the width.
31. The lintels support stone or brick masonry over the openings and transfer all the loads to the side walls by

A. Arch action

B. Linear action

C. Tapered bars

D. Threaded rods

Explanation: A lintel transfers the load from the masonry above it to the side walls by creating a triangular-shaped "arch action." This triangular area of masonry is self-supporting, and the lintel only carries the load within this triangle.
32. Sometimes, the tread is projected outwards for aesthetics or to provide more space. This projection is called the

A. Going

B. Nosing

C. Riser

D. Waist slab

Explanation: Nosing is the projecting part of a stair tread beyond the face of the riser. It is primarily for aesthetic purposes and to provide more foot space on the stair.
33. For design of slab as per IS 456-2000, the diameter of reinforcing bars shall not exceed

A. $1/6^{th}$ of total thickness of the slab

B. $1/8^{th}$ of total thickness of the slab

C. $1/10^{th}$ of total thickness of the slab

D. $1/12^{th}$ of total thickness of the slab

Explanation: As per IS 456-2000, Clause 26.5.2.2, the diameter of a reinforcing bar in a slab should not exceed one-eighth of the total thickness of the slab.
34. Sunshades are designed as

A. one way slab

B. cantilever slabs

C. two way slab

D. continuous slab

Explanation: Sunshades (chajjas) are typically designed as cantilever slabs, projecting from a wall to provide protection from sun and rain. They are supported at one end only, which is why they are classified as cantilever structures.
35. Torsional reinforcement in a two way slab is not provided when

A. Continuous edges in all sides

B. Two long edges are continuous

C. Two short edges are discontinuous

D. Three edges are discontinuous

Explanation: Torsional reinforcement is provided in two-way slabs at discontinuous corners. If all four edges are continuous, there is no corner discontinuity, and thus, no need for torsional reinforcement.
36. As per IS 456-2000 the characteristic strength in $N/mm^{2}$ concrete for ordinary concrete ranges from

A. $10-15$

B. $15-25$

C. $10-20$

D. $15-30$

Explanation: As per IS 456-2000, ordinary concrete is defined by grades M10, M15, and M20. Their characteristic compressive strengths are 10 $N/mm^2$, 15 $N/mm^2$, and 20 $N/mm^2$ respectively. Therefore, the range is from 10-20 $N/mm^2$.
37. As per IS 456-2000, unit weight of concrete with reinforcement shall be

A. $19~kN/m^{3}$

B. $20~kN/m^{3}$

C. $22~kN/m^{3}$

D. $25~kN/m^{3}$

Explanation: As per IS 456-2000, the unit weight of plain concrete is taken as 24 $kN/m^3$, and the unit weight of reinforced concrete is taken as 25 $kN/m^3$ for design calculations.
38. As per IS 456-2000, the permissible shear stress of concrete without reinforcement is calculated using,

A. The number of main reinforcement

B. Depth of beam

C. Grade of steel

D. Percentage of steel and grade of concrete

Explanation: The permissible shear stress of concrete, without shear reinforcement, is denoted as $\tau_c$. As per IS 456-2000, the value of $\tau_c$ depends on the percentage of tensile steel ($p_t$) and the grade of concrete ($f_{ck}$).
39. The IS code used for the design of plain and reinforced concrete is

A. IS 456-2000

B. IS 800-2007

C. IS 883-1994

D. IS 2858-1984

Explanation: IS 456-2000 is the Indian Standard for Plain and Reinforced Concrete - Code of Practice. IS 800-2007 is for steel structures, and IS 883-1994 is for timber structures.
40.
1. A doubly reinforced beam is provided to increase the strength of a beam with limited dimensions.
2. To increase the ductility of the beam is another reason for the provision of doubly reinforced sections.

A. 1 and 2 are true

B. 1 and 2 are false

C. 1 is true and 2 is false

D. 1 is false and 2 is true

Explanation: Both statements are true. A doubly reinforced beam is used when the beam dimensions are restricted and the moment of resistance of a singly reinforced beam is insufficient. The provision of compression reinforcement also increases the ductility of the beam section.
41. What is the purpose of docking area in a harbour?

A. To monitor ship activity

B. To unload cargo and store goods

C. To control the movement of waves

D. To store water for ships

Explanation: A docking area is a designated space within a harbour for ships to berth for purposes such as unloading and loading cargo, or undergoing maintenance.
42. What is the primary purpose of a Quay Wall in harbour construction?

A. To monitor vessel activities

B. To provide space for unloading cargo from ships

C. To store ships temporarily

D. To filter incoming seawater

Explanation: A quay wall is a solid structure built parallel to the shore. Its primary purpose is to provide a solid face against which ships can moor, and an area for cargo to be loaded and unloaded directly from the ship to the land.
43. Which of the following is not a fixture in rails?

A. Chains

B. Tables

C. Fish plate

D. Bearing plate

Explanation: Fixtures are devices used to secure the rail to the sleepers. Common fixtures include chains, fish plates, and bearing plates. Tables are not a component of a rail system.
44. Rail gauge is the distance between

A. inner faces of the sleepers

B. outer faces of the sleepers

C. outer faces of the rails

D. inner faces of the rails

Explanation: Rail gauge is the clear perpendicular distance between the inner faces of the two rails that form a track.
45. Road Arboriculture means

A. Plantation of trees on both sides of road

B. Well night lighting

C. Well drainage of road

D. A very good road alignment

Explanation: Road arboriculture refers to the practice of planting and maintaining trees and other vegetation along roadsides.
46. The Mass Rapid Transit System (MRTS) is an elevated suburban railway in

A. Chennai

B. Mumbai

C. Delhi

D. Kolkatta

Explanation: The Mass Rapid Transit System (MRTS) in India is an elevated suburban railway system located in Chennai, Tamil Nadu.
47. In consistency of soil, the limits are expressed in terms of

A. Percentage of Water content

B. Area

C. Volume

D. All of the mentioned

Explanation: The consistency limits of soil, including liquid limit, plastic limit, and shrinkage limit, are defined and expressed in terms of the percentage of water content at which the soil changes its state.
48. In particle size classification ______ system, the soils are classified according to

A. Grain size

B. Properties of soil

C. Shapes of particles

D. Solubility

Explanation: In various particle size classification systems, such as the Unified Soil Classification System, soils are categorized based on the size of their constituent grains.
49. Which of the following is not useful for Engineering purpose, as proposed by Atterberg?

A. Plastic limit

B. Liquid limit

C. Solid limit

D. Shrinkage limit

Explanation: The Atterberg limits, which are used to determine the consistency of fine-grained soils, consist of the liquid limit, plastic limit, and shrinkage limit. The term "solid limit" is not one of the Atterberg limits used in engineering.
50. In soil classification, inorganic silt with high plasticity is denoted as

A. MH

B. ML

C. LM

D. MS

Explanation: According to the Unified Soil Classification System, inorganic silts are denoted by the letter 'M'. The letter 'H' indicates high plasticity (Liquid Limit > 50%), and 'L' indicates low plasticity (Liquid Limit < 50%). Therefore, MH represents inorganic silt with high plasticity.
51. Plasticity Index $(I_{P})$ is calculated as

A. $I_{P}=LL-PL$

B. $I_{P}=LL-SL$

C. $I_{P}=PL-SL$

D. $I_{P}=SL-PL$

Explanation: The plasticity index ($I_{P}$) is a measure of the plasticity of a soil. It is the numerical difference between the liquid limit (LL) and the plastic limit (PL). The formula is $I_{P} = LL - PL$.
52. Soil mass has a

A. Single phase system

B. Two phase system

C. Three phase system

D. Four phase system

Explanation: A soil mass typically consists of three phases: solid particles, water, and air. This is referred to as a three-phase system.
53. The part of a bridge structure provided to distribute the load coming from the superstructure to the substructure and also to allow for longitudinal and angular movements

A. Girder (or) truss

B. Decking

C. Approaches to the bridge

D. Bearing

Explanation: Bearings are components that transfer the loads from the bridge deck and superstructure to the piers and abutments. They also accommodate movements, such as expansion and contraction, rotation, and translation, to prevent damage to the structure.
54. Maximum dry density is got at

A. Minimum water content

B. Maximum water content

C. Optimum moisture content

D. Optimum water content

Explanation: The maximum dry density of a soil is achieved at a specific water content known as the optimum moisture content. At this point, the soil particles are packed most efficiently, leading to maximum density.
55. One of the natural factors influencing camber is

A. type of material used for wearing coarse

B. topography of the area

C. nature of subsoil met with

D. the amount of rainfall

Explanation: Camber, or the cross-slope of a road, is provided to drain rainwater from the road surface. Therefore, the amount of rainfall in the region is a critical factor influencing the required camber.
56. The pavement layers that transmit the vertical (or) compressive stresses to the lower layers by grain to grain transfer through the point of contact in the granular structure is called

A. flexible pavement

B. rigid pavement

C. concrete pavement

D. block pavement

Explanation: Flexible pavements are composed of several granular layers that transfer load to the subgrade by grain-to-grain contact, distributing the compressive stress over a larger area.
57. Compared to a level surface, on a descending gradient the stopping sight distance is

A. Less

B. More

C. Same

D. Dependent on the speed

Explanation: On a descending gradient, gravity assists the vehicle's motion, increasing the braking distance required to stop. Therefore, the stopping sight distance is more than on a level surface.
58. Choose the correct statement from the following regarding super elevation
(i) It results, faster and safer movement of vehicles on curves
(ii) Maintenance cost of road on curve is reduced

A. (i) only true

B. (ii) only true

C. both (i) and (ii) true

D. both (i) and (ii) false

Explanation: Super elevation (or banking of roads) is the transverse slope provided to counteract the centrifugal force, allowing vehicles to take curves at higher speeds safely. This reduces the lateral pressure on the road, which in turn can lead to reduced maintenance costs.
59. The changes in gradient and vertical curve are covered under which type of alignment?

A. Horizontal alignment

B. Vertical alignment

C. Geometric alignment

D. Highway

Explanation: Vertical alignment refers to the profile of the road along its length, which includes gradients (upward or downward slopes) and vertical curves to provide a smooth transition between them.
60. Exceptional gradient shall not exceed in plains

A. $1:20$

B. $1:15$

C. $1:25$

D. $1:30$

Explanation: As per Indian Roads Congress (IRC) standards, the exceptional gradient in plain or rolling terrain should not be steeper than 1 in 20.
61. Choose the correct statement from the following.
(i) The end support of the bridge is known as abutment.
(ii) The intermediate support of the bridge is known as pier.

A. (i) only true

B. (ii) only true

C. both (i) and (ii) true

D. both (i) and (ii) false

Explanation: Abutments are the supports at the ends of a bridge that carry the load from the superstructure and also retain the earth fill of the bridge approach. Piers are the intermediate supports located between the abutments. Both statements are correct.
62. The roads passing through hilly terrain and leading to the villages and towns near hills are called

A. Village road

B. State highway

C. Hill road

D. City road

Explanation: Roads built to navigate the difficult topography of hilly regions, and to connect communities in those areas, are specifically called hill roads.
63. What is the main purpose of using fine stone dust (or) screenings in a Water Bound Macadam (WBM) road?

A. To provide waterproofing

B. To bind the coarse aggregates and fill the voids

C. To act as a sub-base material

D. To increase the thickness of the road

Explanation: In a Water Bound Macadam (WBM) road, fine stone screenings are spread over the coarse aggregate layer. Their main purpose is to fill the voids between the aggregates and, when watered and rolled, act as a binding agent to create a stable, interlocked layer.
64. Which one of the following factors is not to be considered while fixing thickness of the slab in concrete roads?

A. Wheel load

B. Friction between slab and sub-grade

C. Temperature variation

D. Rainfall variation

Explanation: The thickness of a rigid concrete pavement slab is determined by factors such as the design wheel load, the subgrade support, and stresses caused by temperature and moisture variations. Rainfall variation is not a direct factor in determining the thickness of a concrete pavement slab.
65. Breast walls in hill roads is provided to

A. prevent the cut hill from sliding

B. prevent avalanches along hill roads

C. drain away water from upper regions

D. prevent flooding along hill roads

Explanation: Breast walls are retaining walls built to support the earth fill of a hillside and prevent the hill from sliding or eroding away, particularly where a road has been cut into the slope.
66. In image analysis, which of the following refers to a "natural" color composite?

A. Red, green and blue bands

B. Infrared, red and green bands

C. Green, yellow and blue bands

D. Red, blue and yellow bands

Explanation: A natural color composite in remote sensing is an image created by assigning the red, green, and blue spectral bands to the corresponding red, green, and blue colors of the display monitor. This creates an image that appears similar to what the human eye would see.
67. Which one of the following attributes is not associated with digital maps?

A. Colour

B. Symbology

C. Legends

D. South arrow

Explanation: Digital maps are primarily composed of data, not physical orientation. While they may display an arrow indicating north, a static "South arrow" is not an inherent attribute of a digital map in the same way that colour, symbology (symbols), and legends are.
68. Which of the following indicates the correct set of the combination of total station?

A. Theodolite, compass

B. Electronic theodolite, EDM

C. EDM, theodolite

D. Electronic theodolite, compass

Explanation: A Total Station is an electronic surveying instrument that combines an electronic theodolite (for measuring horizontal and vertical angles) and an Electronic Distance Measurement (EDM) device.
69. Choose the correct statement about GIS. (i) In raster data type, digital image represented in grids. (ii) Raster data also allows easy implementation of overlay operations, which are more difficult with vector data.

A. (i) true and (ii) false

B. (i) false and (ii) true

C. both (i) and (ii) true

D. both (i) and (ii) false

Explanation: A raster data model represents data as a grid of pixels or cells, where each cell has a specific value. This is a common way to represent satellite imagery and aerial photographs. Overlay operations (combining layers) are generally simpler and computationally faster with raster data because the cell-based structure is uniform. Therefore, both statements are correct.
70. Over turning of vehicles on the curve can be avoided by introducing

A. compound curve

B. simple curve

C. reverse curve

D. transition curve

Explanation: Overturning is a critical consideration on curves. A transition curve is a gradually varying curve introduced between a straight section and a circular curve to gradually introduce superelevation, allowing vehicles to change direction and speed smoothly and safely without overturning.
71. Passive remote sensing is when

A. The remote sensing is done from the ground

B. The remote sensing is done from an aircraft

C. Satellites are used for remote sensing

D. External energy source is used for remote sensing

Explanation: Passive remote sensing systems detect and measure natural radiation that is emitted or reflected by the object or scene being observed. This relies on an external energy source such as the sun. Active remote sensing systems, by contrast, emit their own energy to illuminate the object.
72. Which of the following can be affected by atmospheric path disturbances?

A. Modern GPS surveying

B. Chain surveying

C. Compass surveying

D. Resection method

Explanation: Modern GPS surveying relies on radio signals transmitted from satellites. These signals can be delayed or distorted as they pass through the Earth's atmosphere (e.g., the ionosphere and troposphere), which is a common source of error known as atmospheric path disturbances.
73. The least count of Vernier of an ordinary theodolite is

A. $20''$

B. $20'$

C. $20^{\circ}$

D. $0''$

Explanation: The least count of a Vernier scale is the smallest measurement that can be made with the instrument. For an ordinary theodolite, the least count of its Vernier scale is typically 20 seconds ($20''$).
74. The multiplying constant in the distance formula by Tacheometry is given by

A. $f+d$

B. $f-d$

C. $f/i$

D. $i/f$

Explanation: In tacheometry, the horizontal distance (D) to a staff is calculated using the formula: $D = KS + C$. Here, 'K' is the multiplying constant, which is equal to the ratio of the focal length of the objective lens ($f$) to the staff intercept ($i$), i.e., $K = f/i$. 'C' is the additive constant, which is $f+d$.
75. Which formula is used for calculating length of the curve ($l$) in circular curve? Where R – Radius of the curve Δ – Deflection angle

A. $l=\frac{R\Delta}{180}$

B. $l=\frac{\pi R\Delta}{180}$

C. $l=\frac{R\Delta}{360}$

D. $l=\frac{\pi R\Delta}{360}$

Explanation: The length of a circular curve is the length of the arc from the point of curve to the point of tangency. It is calculated by the formula $l = \frac{\pi R\Delta}{180}$, where R is the radius and $\Delta$ is the deflection angle in degrees.
76. In which formula is used for calculating tangent length (T) of circular curve? Where R – Radius of the curve Δ – Deflection angle

A. $T=R~sin\frac{\Delta}{2}$

B. $T=R~cos\frac{\Delta}{2}$

C. $T=R~tan\frac{\Delta}{2}$

D. $T=R~sec\frac{\Delta}{2}$

Explanation: The tangent length of a circular curve is the distance from the point of intersection of the two tangents to the point of curve or the point of tangency. It is calculated as $T = R~tan(\Delta/2)$, where R is the radius and $\Delta$ is the deflection angle.
77. Cross-sectioning and longitudinal sectioning is

A. Simple levelling

B. Differential levelling

C. Profile levelling

D. Check levelling

Explanation: Profile levelling is a type of levelling used to determine elevations along a line or a series of points, such as the centerline of a road or sewer. It includes both longitudinal sectioning (determining the profile along the main line) and cross-sectioning (determining the profile at right angles to the main line).
78. The additive constant of a Tacheometer is denoted by

A. $\frac{f}{i}$

B. $\frac{i}{f}$

C. $f \times d$

D. $f+d$

Explanation: In tacheometry, the horizontal distance formula is $D = KS + C$. The additive constant 'C' is the sum of the focal length of the objective lens ($f$) and the distance from the vertical axis of the instrument to the objective lens ($d$), i.e., $C = f+d$.
79. For a well-conditioned triangle, no angle should be less than

A. $20^{\circ}$

B. $30^{\circ}$

C. $45^{\circ}$

D. $90^{\circ}$

Explanation: In triangulation, a well-conditioned triangle is one where small errors in angular measurements do not significantly affect the accuracy of the computed side lengths. For this reason, it is considered ideal to have angles between $30^{\circ}$ and $120^{\circ}$. An angle less than $30^{\circ}$ is considered to be a poorly conditioned triangle.
80. The error in measured length due to sag of a chain (or) tape is known as

A. Instrumental error

B. Compensating error

C. Positive error

D. Negative error

Explanation: Sag is the vertical drop of a tape or chain due to its own weight when held between two supports. This causes the measured length to be longer than the true horizontal distance, leading to a positive error. The correction applied for sag is therefore negative.
81. When the length of a chain along a slope of is (l), the correction for slope required is

A. $l(1-sin~\theta)$

B. $l(1-tan~\theta)$

C. $l(1-cos~\theta)$

D. $l(1-cos^{2}\theta)$

Explanation: The correction for slope is applied to the measured length on a sloping ground to obtain the true horizontal distance. If the measured length is $L$ and the angle of slope is $\theta$, the horizontal distance is $L \cos\theta$. The correction is the difference between the measured length and the horizontal distance, which is $L - L \cos\theta = L(1 - \cos\theta)$.
82. As a general rule, the accuracy of elevations obtained from a contour map is typically limited to

A. Contour interval

B. $\frac{1}{2}\times$ contour interval

C. $\frac{1}{4}\times$ contour interval

D. 2 part of contour interval

Explanation: The accuracy of elevations interpolated from a contour map is generally limited to half of the contour interval. This is because values are estimated between the contour lines, and half the interval represents a reasonable degree of precision.
83. The survey which in observations of heavenly bodies such as sun or any other fixed star, is known as

A. Cadestral survey

B. Astrological survey

C. Photographic survey

D. Astronomical survey

Explanation: An Astronomical survey is a type of survey that uses observations of celestial bodies like the sun or stars to determine the absolute location and orientation of points on the Earth's surface.
84. The magnetic bearing of a line is $62^{\circ}30'$. What is the true bearing if the magnetic declination is $4^{\circ}10'E$?

A. $4^{\circ}10'$

B. $58^{\circ}20'$

C. $62^{\circ}30'$

D. $66^{\circ}40'$

Explanation: When the magnetic declination is East (E), the true bearing is calculated by adding the declination to the magnetic bearing. The formula is: True Bearing = Magnetic Bearing + Declination. Here, True Bearing = $62^{\circ}30' + 4^{\circ}10' = 66^{\circ}40'$.
85. In chain surveying, reciprocal ranging is adopted when the two ends of chain line are

A. mutually invisible

B. too distant

C. visible

D. separated by a valley

Explanation: Reciprocal ranging is a method used in chain surveying when the two end stations of a line are mutually invisible due to an obstacle such as a hill or rising ground. It involves setting up intermediate points from both ends.
86. The water obtained from the tube well is known as

A. Surface water

B. Ground water

C. Potable water

D. Run off

Explanation: Water obtained from a tube well, which taps into an underground aquifer, is a type of groundwater.
87. Centrifugal pumps transfer energy from

A. Fluid to rotor

B. Rotor to fluid

C. Draft to rotor

D. Rotor to draft

Explanation: In a centrifugal pump, the impeller (rotor) rotates and imparts kinetic energy to the fluid. The fluid then flows out and converts this kinetic energy into pressure energy. Thus, energy is transferred from the rotor to the fluid.
88. Which one of the following is not used to measure the pressure of liquid?

A. Piezometer

B. Manometer

C. Differential manometer

D. Pycnometer

Explanation: Piezometers, manometers, and differential manometers are all instruments used to measure the pressure of fluids. A pycnometer is a device used to determine the density or specific gravity of a substance, not its pressure.
89. In Manning's formula, the value of Chezy's constant 'C' is calculated by (Where, m = Hydraulic mean depth N = Manning’s constant)

A. $C=\frac{1}{M}N^{\frac{1}{5}}$

B. $C=\frac{1}{M}N^{\frac{1}{6}}$

C. $C=\frac{1}{N}M^{\frac{1}{6}}$

D. $C=\frac{1}{N}M^{\frac{1}{5}}$

Explanation: According to Manning's formula, the Chezy's constant (C) is given by the relation $C = \frac{1}{n}R^{1/6}$, where 'n' is Manning's roughness coefficient and 'R' is the Hydraulic radius. The option uses 'N' and 'M' in place of 'n' and 'R' respectively. Thus, $C = \frac{1}{N}M^{1/6}$.
90. The Trapezoidal section of a channel will be most economical, when its wetted perimeter is

A. Maximum

B. Minimum

C. Zero

D. Infinity

Explanation: For a channel section to be hydraulically most economical (i.e., to carry maximum discharge for a given cross-sectional area and slope), its wetted perimeter must be a minimum. This minimises the frictional resistance to flow.
91. Hydraulic Mean Depth (m) is calculated using the formula given. Where A is area and P is the Wetted Perimeter

A. $\frac{ZA}{P}$

B. $\frac{P}{ZA}$

C. $P/A$

D. $\frac{A}{P}$

Explanation: The Hydraulic Mean Depth (R), also known as the Hydraulic Radius, is a measure of the efficiency of a channel section in carrying fluid. It is defined as the ratio of the cross-sectional area of flow (A) to the wetted perimeter (P). The formula is $R = \frac{A}{P}$.
92. The range for co-efficient of discharge ($C_{d}$) for a venturimeter is

A. 0.6 to 0.7

B. 0.7 to 0.8

C. 0.8 to 0.9

D. 0.95 to 0.99

Explanation: The coefficient of discharge ($C_d$) for a venturimeter is very high, typically ranging from 0.95 to 0.99. This is because the venturimeter is designed to cause very little head loss.
93. Co-efficient of contraction $(C_{c})$ is equal to

A. $\frac{a_{c}^{2}}{3a}$

B. $\frac{a_{c}}{a}$

C. $\sqrt{a_{c}\times a}$

D. $a_{c}\times a$

Explanation: The coefficient of contraction ($C_c$) is defined as the ratio of the area of the fluid jet at the vena contracta ($a_c$) to the area of the orifice ($a$). The formula is $C_c = \frac{a_c}{a}$.
94. If the cross-sectional area of flow and wetted perimeter of open channel is 16 $m^{2}$ and 8 m respectively. What is the Hydraulic radius of open channel?

A. 0.5 m

B. 2 m

C. 128 m

D. 16 m

Explanation: The Hydraulic Radius (R) is calculated as the ratio of the Area of flow (A) to the Wetted Perimeter (P). Given A = 16 $m^2$ and P = 8 m, then $R = \frac{A}{P} = \frac{16}{8} = 2~m$.
95. The term 'Z' is known as

A. Potential Energy

B. Pressure Energy

C. Potential Energy per unit weight

D. Pressure Energy per unit weight

Explanation: In the Bernoulli's equation, the term 'Z' refers to the elevation head, which represents the potential energy per unit weight of the fluid relative to a datum.
96. For Laminar flow, Reynolds number is

A. < 2000

B. > 4000

C. > 5000

D. > 6000

Explanation: Laminar flow is characterized by fluid particles moving in smooth, parallel layers without intermixing. This type of flow occurs at low velocities and is defined by a Reynolds number ($R_e$) less than 2000. For pipe flow, the transition range is $R_e = 2000 - 4000$, and for turbulent flow, $R_e > 4000$.
97. The Hydraulic mean depth for a circular pipe of diameter 160 mm when running full is

A. 80 mm

B. 40 mm

C. 20 mm

D. 107 mm

Explanation: For a circular pipe running full, the hydraulic mean depth (R) is the ratio of the cross-sectional area ($A = \frac{\pi}{4}D^2$) to the wetted perimeter ($P = \pi D$). So, $R = \frac{A}{P} = \frac{\frac{\pi}{4}D^2}{\pi D} = \frac{D}{4}$. Given $D = 160~mm$, $R = \frac{160}{4} = 40~mm$.
98. In a laminar flow in pipe, the velocity is maximum at

A. Perimeter

B. Uniform in the section

C. Center

D. $\frac{1}{3}$ of depth

Explanation: In a laminar flow through a circular pipe, the velocity profile is parabolic. The velocity is zero at the pipe walls (perimeter) and reaches its maximum value at the center of the pipe.
99. Pitot-tube is used for measurement of

A. Velocity at a point

B. Flow

C. Pressure

D. Discharge

Explanation: A Pitot tube is a device used to measure the velocity of fluid at a specific point in a flow stream. It does so by converting the kinetic energy of the flow into potential energy.
100. The force per unit area is called

A. Pressure

B. Strain

C. Surface tension

D. Density

Explanation: Pressure is a measure of the force applied per unit area. It is typically expressed in units of Pascals (Pa) or $N/m^2$.
101. One of the major uses of computers in construction project management is

A. Manual labour estimation

B. Designing and drafting

C. Project scheduling and planning

D. Sand quality testing

Explanation: Computers are widely used in construction management for complex tasks like project scheduling and planning, which involves creating and managing project timelines, resource allocation, and dependencies.
102. MS word is an example of

A. An operating system

B. A processing device

C. Application software

D. An input device

Explanation: MS Word is a type of application software that is designed for end-users to perform specific tasks, such as creating and editing documents.
103. Cause for major or great earthquake is due to

A. Poor building construction

B. Heavy floods

C. Weak landform

D. Area in tectonic plate boundary

Explanation: The most significant earthquakes are caused by the movement and interaction of the Earth's tectonic plates along their boundaries.
104. Earthquake preparedness can be achieved by

A. Following BIS codes for earthquake design and construction

B. Less storeyed buildings

C. Providing good foundation

D. Use of RCC structures

Explanation: The most effective way to ensure earthquake preparedness in construction is to adhere to specific design and construction standards, such as the BIS (Bureau of Indian Standards) codes for earthquake-resistant design.
105. Which phase of disaster management focuses on restoring normal life after a disaster?

A. Preparedness

B. Response

C. Recovery

D. Mitigation

Explanation: The recovery phase of disaster management focuses on rebuilding and restoring infrastructure and services to help the affected community return to normalcy after a disaster has occurred.
106. Which curve is used for cash flow analysis for owner and contractor?

A. L curve

B. J curve

C. C curve

D. S curve

Explanation: The S-curve is a graphical representation used in project management to track cash flow over time. It typically shows the cumulative cost or resource usage plotted against time, forming a characteristic "S" shape.
107. Stages of cost control

A. Pre-contract stages and design stages

B. Post contract stages and design stages

C. Pre-contract stages and post contract stages

D. Design stages and execution stages

Explanation: Cost control in a construction project is a continuous process that involves two main stages: the pre-contract stage (estimating and bidding) and the post-contract stage (managing costs during execution).
108. EMD stands for

A. Earliest Money Deposit

B. Earning Money Deposit

C. Earnest Money Deposit

D. Early Monetary Deposit

Explanation: EMD stands for Earnest Money Deposit, which is a refundable security deposit paid by a bidder to an owner or developer to show genuine intent to enter into a contract.
109. N.M.R. stands for

A. Nominal Muster Roll

B. Normal Muster Roll

C. Nominal Maintenance Register

D. Normal Maintenance Register

Explanation: N.M.R. stands for Nominal Muster Roll, a register used in construction and other industries to record the daily attendance and wages of temporary or casual labourers.
110. Which one is not a type of contract?

A. Lumpsum

B. Total price

C. Cost plus

D. Incentive contract

Explanation: Contract types in construction include Lump Sum, Cost Plus, and Incentive contracts. "Total price" is a payment term, not a distinct contract type.
111. In contract document 'Bill of quantities' means

A. Which furnishes the measure of each of the items of work to be done

B. Describes the quality and workmanship

C. Methods of payment and liabilities of parties

D. Billing procedures for different nature of work

Explanation: A Bill of Quantities (BOQ) is a document used in tendering and contracting that provides a detailed list of all the materials and labour required for a project, along with their measured quantities.
112. Which noise level personal protective device required?

A. 0-10 db

B. 10-20 db

C. 20-30 db

D. 30 db and above

Explanation: Prolonged exposure to noise levels of 30 dB and above can cause health problems and is a typical threshold where personal protective devices, such as earplugs or earmuffs, are recommended or required in an occupational setting.
113. The time by which activity completion time can be delayed without affecting the start of succeeding activities, is known as

A. Duration

B. Total float

C. Free float

D. Interfering float

Explanation: Free float is the amount of time that an activity can be delayed without affecting the start time of any succeeding activity. It is the time available before the early start of the next activity.
114. The entire construction project work is divided into smaller pieces of discrete tasks which consume a definite time. The term used to describe the above is called as

A. Resource

B. Cost

C. Activity

D. Event

Explanation: An activity in a project network is a task or a discrete unit of work that consumes a specific amount of time and resources.
115. The amount of time by which the finish of an activity can be delayed without delaying the earliest starting time for the following activity

A. Latest start time

B. Free float

C. Slack time

D. Critical path

Explanation: This is the precise definition of Free float. It is the delay an activity can tolerate without affecting the early start of its successor.
116. Which of the following rules are applied for determining a critical activity?
(i) The early start and late start times for an activity are same.
(ii) The early finish and late finish time for an activity are same.
(iii) The early start and late starts time need not be same. (iv) The early finish and late finish time need not be same.

A. (i), (iii) are correct

B. (i), (ii) are correct

C. (iii), (iv) are correct

D. (i), (ii), (iii) correct

Explanation: A critical activity is one that has zero float. This means its early start time (ES) is equal to its late start time (LS), and its early finish time (EF) is equal to its late finish time (LF). Therefore, both statements (i) and (ii) are correct.
117. A critical activity has

A. Maximum float

B. Minimum float

C. Zero float

D. Average float

Explanation: By definition, a critical activity is a task on the critical path that has no float, meaning any delay will delay the entire project. Its float is zero.
118. 'BOT' is a project delivery model adopted for large infrastructure projects of nation which denotes

A. Build-Operate-Transfer

B. Build-Orient-Transfer

C. Begin-Orient-Transmit

D. Build-Orient-Transport

Explanation: BOT is a common project financing model for large infrastructure projects. It stands for Build-Operate-Transfer, where a private company builds, operates, and then transfers the project to the public sector after a specified period.
119. The earliest method used for planning of projects was

A. CPM

B. PERT

C. Bar Chart

D. Milestone Chart

Explanation: The Bar Chart, also known as the Gantt chart, was one of the earliest and simplest project planning tools. It visually represents the project schedule with bars showing the start and end dates of activities.
120. Bar charts are suitable only for

A. Small size projects

B. Medium size projects

C. Large size projects

D. No specific project size

Explanation: Bar charts are simple and easy to create and understand, making them suitable for planning and managing small-sized projects. For larger, more complex projects, network-based methods like CPM and PERT are more appropriate as they show the dependencies between activities.
121. Which will bring down the overall painting cost, reduce the weight and increase the durability of paints?

A. Solvents

B. Adulterants

C. Pigments

D. Tung oil

Explanation: Adulterants are substances added to paints, often to reduce cost, improve workability, and sometimes to increase durability. They are typically inexpensive fillers.
122. The method of covering various components of a building with a plastic material to form a durable surface

A. Concreting

B. Flooring

C. Plastering

D. Roofing

Explanation: Plastering is the process of applying a plastic material, such as mortar or cement paste, to a surface to create a durable finish.
123. Plastic emulsion paint is ______ based wall paint.

A. Water

B. Lime

C. Surkhi

D. Cement

Explanation: Plastic emulsion paints are a type of paint where pigments are suspended in a polymer emulsion that is diluted with water as a solvent. They are commonly used for interior walls.
124. For colour washing on new works

A. the primary coat shall be white wash

B. the primary coat shall be colour wash

C. the primary coat shall be painting

D. no primary coat is required

Explanation: When applying color wash on new works, a primary coat of white wash is typically applied first to provide a smooth, uniform, and light-colored base for the color wash.
125. A semi-rigid material which forms an excellent impervious layer for damp proofing is known as

A. Bitumen

B. Tar

C. Aluminal

D. Mastic asphalt

Explanation: Mastic asphalt is a type of semi-rigid waterproof material that is melted and applied as a continuous, jointless layer, making it highly effective for damp proofing and waterproofing basements and roofs.
126. The lowest part of a structure which transmit the load to the soil known as

A. Super-structure

B. Plinth

C. Foundation

D. Basement

Explanation: The foundation is the lowest part of a structure that transmits the loads from the building to the underlying soil or rock.
127. The development of fine hair cracks in plastered surface is called as

A. Popping

B. Crazing

C. Flaking

D. Blistering

Explanation: Crazing is the formation of a network of fine, shallow, and interconnected hairline cracks on the surface of cement plaster or concrete.
128. Match the correct one from the following:

A. A-3, B-4, C-2, D-1

B. A-4, B-3, C-1, D-2

C. A-4, B-3, C-2, D-1

D. A-3, B-1, C-4, D-2

129. The lowest part of the building which is in direct contact with ground is

A. Building

B. Foundation

C. Super structure

D. Floor level

Explanation: The foundation is the component of a structure that directly interfaces with the ground, serving to transfer and distribute the building's loads to the soil below.
130. Which of the following is a key benefit of using fly ash bricks in construction?

A. High porosity and poor dimensional accuracy

B. High water absorption and reduced strength

C. Utilization of industrial waste and improved thermal insulation

D. Requirement of excessive mortar due to irregular shape

Explanation: Fly ash bricks are a key component of sustainable construction because they utilize a waste product from power plants, which helps with waste disposal. They also offer improved thermal insulation properties compared to traditional clay bricks.
131. Which of the following is considered a key characteristic of green building materials?

A. High embodied energy and non-recyclability

B. Use of non-renewable resources exclusively

C. Sustainability, low environmental impact and recyclability

D. Expensive and difficult to source materials

Explanation: Green building materials are characterized by their sustainability, low environmental impact throughout their lifecycle, and their ability to be recycled or reused.
132. Which of the following is the most appropriate application of Portland Pozzolana Cement (PPC)?

A. Construction of runways and airfields requiring quick setting

B. Marine structures and hydraulic structures works exposed to sulphate attacks

C. Cold weather concreting requiring rapid strength gain

D. Repair works requiring quick setting and high early strength

Explanation: Portland Pozzolana Cement (PPC) is highly resistant to sulfate and chloride attacks. This makes it an ideal choice for marine and hydraulic structures as it provides better durability in aggressive environments.
133. What type of admixture is most suitable option in the case of emergency repair work?

A. Retarders

B. Accelerators

C. Plasticizers

D. Air-entraining agents

Explanation: Accelerators are admixtures used to increase the rate of hydration and strength development in concrete. This is particularly useful in emergency repair work where quick setting and early strength gain are critical.
134. Which one of the following materials is one of the most effective retarding agents used as admixture?

A. Common sugar

B. Calcium chloride

C. Fly ash

D. Blast furnace slag

Explanation: Common sugar is a highly effective, albeit potent, retarding agent. It significantly delays the setting time of concrete and is sometimes used in small quantities in special mixes.
135. Which one of the following factors is not affecting workability in concrete?

A. type of superplasticizers

B. dosage of superplasticizers

C. water cement ratio

D. volume of the concrete

Explanation: Workability is the ease with which concrete can be mixed, transported, and placed without segregation. Factors like the type and dosage of superplasticizers and the water-cement ratio directly affect workability. The overall volume of the concrete being placed does not affect the workability of the mix itself.
136. Match correctly the laboratory tests for cement with corresponding property.
(a) Vicat Apparatus - 1. Soundness of cement
(b) Le-chatelier apparatus - 2. Initial setting time of cement
(c) Slump test - 3. Workability of cement concrete
(d) Fineness test - 4. Mean size of grains of cement

A. A-1, B-2, C-3, D-4

B. A-1, B-4, C-3, D-2

C. A-3, B-4, C-2, D-1

D. A-2, B-1, C-3, D-4

Explanation: (a) Vicat Apparatus is used to determine the initial and final setting times of cement. This matches option 2.
(b) Le-chatelier apparatus is used to test the soundness of cement. This matches option 1.
(c) Slump test is used to determine the workability of fresh cement concrete. This matches option 3.
(d) Fineness test is used to measure the mean size of cement grains. This matches option 4.
The correct combination is (a)-2, (b)-1, (c)-3, (d)-4, which corresponds to option D.
137. The age of a log of timber can be estimated by

A. diameter of pith

B. thickness of bark

C. number of annular ring

D. number of medullary ray

Explanation: The age of a tree, and thus a log of timber, can be accurately estimated by counting the number of annual rings (also known as annular rings) in its cross-section. Each ring represents one year of growth.
138. The method of arranging bricks, such that the individual units are tied together is called as

A. Closer

B. Bond

C. Horizontal course

D. Vertical course

Explanation: A bond in masonry is the arrangement of bricks or stones in a wall to ensure that the individual units are tied together and the load is evenly distributed throughout the wall.
139. No fines concrete is

A. Light weight concrete

B. Heavy weight concrete

C. Fibre reinforced concrete

D. Ferro concrete

Explanation: No-fines concrete is a type of lightweight concrete that consists of coarse aggregate, cement, and water, with no fine aggregate (sand) used. This results in a mix with a high void ratio and a lower density, making it a lightweight concrete.
140. ______ of the following sand type is excellent for use in mortar and concrete work.

A. Sea sand

B. Clayey sand

C. Pit sand

D. River sand

Explanation: River sand is considered excellent for use in mortar and concrete because it is typically well-graded and free from organic impurities, clay, or salt content.
141. The fineness of cement is tested by

A. Air content method

B. Air-permeability method

C. Le-chatelier apparatus

D. Vicat's apparatus

Explanation: The fineness of cement, which refers to the particle size, is most commonly tested using the Air-permeability method, which measures the specific surface area of the cement powder.
142. When the concrete is conveyed from the mixer to the point of placement through pipes, it is called the

A. pipe concrete

B. pumped concrete

C. sprinkling concrete

D. wrapping concrete

Explanation: The process of conveying concrete through pipes using a pump is known as pumped concrete. This method is efficient for large-scale concrete placement.
143. Dry rot in timber is caused by

A. Lack of ventilation

B. Lack of light

C. Immersion in water

D. Alternative wet and dry atmosphere

Explanation: Dry rot in timber is a type of decay caused by a specific fungus (Serpula lacrymans). It occurs in unventilated conditions where there is no free circulation of air.
144. As per IS: 565, the sieve sets for coarse aggregate ranges from

A. 40 mm to 4.75 mm

B. 20 mm to 4.75 mm

C. 80 mm to 4.75 mm

D. 100 mm to 4.75 mm

Explanation: As per IS: 565 (which is part of the IS code system), the sieve sizes for grading coarse aggregates typically range from 80 mm to 4.75 mm.
145. Before testing for setting time of cement, one should test for

A. Soundness

B. Strength

C. Fineness

D. Consistency

Explanation: Before conducting a setting time test on cement, it is essential to first determine the consistency of the cement paste. This ensures that the paste has the correct water-cement ratio for the test.
146. CMDA Form - 'A' is used for

A. All types of development

B. Only building plan approval

C. Sub division or layout of land

D. Renew of expired permission

Explanation: CMDA Form 'A' is specifically used for submitting a single building plan for approval in the Chennai Metropolitan Area. Other forms are used for different types of development.
147. Approximate cost of the sanitary arrangements in calculating estimated cost of the building is

A. 2 to 3%

B. 4 to 5%

C. 1 to 2%

D. 3 to 4%

Explanation: The approximate cost of sanitary arrangements, including plumbing and fixtures, is typically estimated at 4 to 5% of the total estimated building cost.
148. The technique of finding the fair price of an existing building or property is known as

A. Estimation

B. Valuation

C. Pricing

D. Costing

Explanation: Valuation is the systematic process of determining the fair market price or value of a property, building, or asset. It considers factors like condition, age, and location.
149. An old building has been purchased at a cost of Rs. 22,000/-. Assuming the future life of the building as 15 years. The amount of annual installment of sinking fund at 4% compound interest is

A. Rs. 1,100

B. Rs. 6,100

C. Rs. 3,000

D. Rs. 500

Explanation: The annual installment of the sinking fund (S) is calculated using the formula: $S = \frac{Si}{(1+i)^n - 1}$, where S is the total fund required, i is the annual interest rate, and n is the number of years. Here, S = Rs. 22,000, i = 0.04, n = 15. The calculation is $S = \frac{22000 \times 0.04}{(1+0.04)^{15} - 1} = \frac{880}{1.8009 - 1} = \frac{880}{0.8009} \approx 1098.74$, which is approximately Rs. 1,100.
150. Special repair estimate is prepared for

A. Maintenance of a building

B. Additional works not in approval

C. Renovation of a structure

D. Preparing revised estimate

Explanation: A special repair estimate is prepared for major repair or renovation work on a structure, such as replacing a roof or a major structural component.
151. 1 square meter is equal to ______ square feet.

A. 35.31

B. 10.67

C. 10.76

D. 35.13

Explanation: The conversion factor from square meters to square feet is 10.7639. Therefore, 1 square meter is approximately equal to 10.76 square feet.
152. Calculate the cost of brickwork of 3.6 cu.m and the rate of brick work is Rs. 320.00 per cu.m

A. Rs. 1150

B. Rs. 1155

C. Rs. 1152

D. Rs. 1160

Explanation: The total cost is calculated by multiplying the volume of work by the rate per unit volume. Cost = $3.6~m^3 \times Rs. 320/m^3$ = Rs. 1152.
153. Work out the volume of earthwork W road embankment for the given area 50 m² and the length as 100 m.

A. $4000~m^{3}$

B. $5500~m^{3}$

C. $5000~m^{3}$

D. $6000~m^{3}$

Explanation: The volume of earthwork is calculated by multiplying the cross-sectional area by the length. Volume = Area $\times$ Length = $50~m^2 \times 100~m$ = 5000 $m^3$.
154. What is the amount of sand required for 1 $m^{3}$ of cement concrete with 1: 1.5: 3 ratio using 20 mm aggregate?

A. $0.856~m^{3}$

B. $0.428~m^{3}$

C. $0.285~m^{3}$

D. $0.328~m^{3}$

Explanation: For 1 $m^3$ of finished wet concrete, the dry volume is approximately 1.54 $m^3$. The ratio is 1 (cement) : 1.5 (sand) : 3 (aggregate). The sum of ratios is $1 + 1.5 + 3 = 5.5$. The volume of sand is the sand ratio divided by the sum of ratios, multiplied by the dry volume. Sand required = $(\frac{1.5}{5.5}) \times 1.54 = 0.42~m^3$. The closest answer is 0.428 $m^3$.
155. The rent which can be lawfully charged on a tenant is known as

A. Lease rent

B. Monopoly rent

C. Nominal rent

D. Standard rent

Explanation: Standard rent is the legally defined maximum rent that a landlord can charge a tenant for a property.
156. Fine aggregate (sand) required for 1 $m^{3}$ of CC 1: 1.5: 3 is

A. $0.50~m^{3}$

B. $0.45~m^{3}$

C. $0.75~m^{3}$

D. $1.00~m^{3}$

Explanation: The volume of sand required for 1 $m^3$ of 1:1.5:3 concrete is calculated as follows: The dry volume of materials needed for 1 $m^3$ of wet concrete is approximately 1.54 $m^3$. The sum of the ratios is $1+1.5+3 = 5.5$. The volume of sand required = $\frac{1.5}{5.5} \times 1.54 = 0.42~m^3$. The provided option of 0.45 $m^3$ is the closest approximation. Note that this calculation is identical to question 154.
157. ______ is the value at the end of utility period without being dismantled.

A. Scrap value

B. Salvage value

C. Book value

D. Gross income

Explanation: Salvage value is the estimated value of an asset at the end of its useful life, assuming it is not dismantled and can be sold or reused in its current form.
158. The quantity of foundation concrete is measured in terms of

A. m

B. $m^{2}$

C. $m^{3}$

D. mm

Explanation: Concrete work, including the foundation, is a three-dimensional quantity. Therefore, it is measured in cubic meters ($m^3$).
159. The degree of accuracy is the computation of areas of quantities.

A. $0.001~m^{2}$

B. $0.01~m^{2}$

C. $0.10~m^{2}$

D. $0.01~m^{3}$

Explanation: In detailed estimation, the area of quantities is computed to an accuracy of 0.01 $m^2$.
160. The area measured correct to the nearest

A. 0.01 sq.m

B. 0.01 sq.cm

C. 0.01 sq.mm

D. 0.02 sq.m

Explanation: In the measurement of quantities for estimation, areas are typically measured correct to the nearest 0.01 sq.m.
161. A semicircular wall of height 3.0 m is provided with radius (internal) 6.9 m. Thickness of wall is 200 mm. Determine the quantity of brickwork required in $m^{3}$.

A. $66~m^{3}$

B. $132~m^{3}$

C. $26.4~m^{3}$

D. $13.2~m^{3}$

Explanation: To find the volume of the brickwork, we calculate the average radius, then use the formula for a half-cylinder. The inner radius is 6.9 m, and the outer radius is $6.9 + 0.2 = 7.1~m$. The average radius is $(6.9 + 7.1)/2 = 7.0~m$. The length of the wall is half the circumference of the circle, which is $\pi \times r_{avg} = 3.14 \times 7.0 = 21.98~m$. The volume of brickwork is length $\times$ thickness $\times$ height = $21.98~m \times 0.2~m \times 3.0~m = 13.188~m^3$. The closest value is 13.2 $m^3$.
162. Honey comb brickwork is measured in

A. sq.mm

B. sq.cm

C. sq.m

D. cu.m

Explanation: Honeycomb brickwork, also known as rat-trap bond, is a type of brickwork with open spaces. As it is not a solid volume, it is measured in terms of area, in square meters (sq.m).
163. In the detailed estimate the volumes are worked out to the nearest

A. $0.001~m^{3}$

B. $0.005~m^{3}$

C. $0.01~m^{3}$

D. $0.05~m^{3}$

Explanation: In a detailed estimate, volumes of materials are calculated to a high degree of precision, typically to the nearest 0.01 $m^3$.
164. The quantity of partition walls and honey comb walls are worked out in

A. m

B. $m^{2}$

C. $m^{3}$

D. $m^{4}$

Explanation: Both partition walls and honeycomb walls are measured in terms of area, as their volume is not solid. Therefore, they are calculated in square meters ($m^{2}$).
165. What is the unit of measurement of lime or cement concrete in foundation?

A. sq. m

B. cu.m

C. r.m

D. quintal

Explanation: Concrete work in foundations is a volumetric quantity, meaning it is measured by its volume. The standard unit of measurement is cubic meters (cu.m).
166. A city with a population of 2 lakhs has to be supplied with water at 180 litres per person per day. Its average daily water supply will be

A. 18 million litres

B. 36 million litres

C. 1.8 million litres

D. 3.6 million litres

Explanation: To calculate the total daily water supply, multiply the population by the per capita water demand. Population = 2 lakhs = $2 \times 10^5$. Water demand = 180 litres/person/day. Total daily demand = $2 \times 10^5 \times 180 = 36 \times 10^6$ litres = 36 million litres.
167. The colour of water can be determined by an instrument known as

A. Turbidimeter

B. Dionic water tester

C. Thermometer

D. Tintometer

Explanation: A Tintometer is an instrument used to measure the color of a substance, including water, by comparing it to a set of standardized color scales.
168. The maximum permissible turbidity for domestic supplies on silica scale is

A. 5 to 10 ppm

B. 10 to 20 ppm

C. 20 to 30 ppm

D. 30 to 40 ppm

Explanation: According to standards, the maximum permissible turbidity for domestic water supplies on the silica scale is 5 to 10 ppm.
169. In water distribution system, the main pipes are laid under roads with a minimum earth filling of

A. 500 mm

B. 750 mm

C. 900 mm

D. 1000 mm

Explanation: Water mains laid under roads require a minimum depth of cover to protect them from traffic loads and other surface disturbances. The standard minimum depth of earth filling is 900 mm from the top of the pipe to the ground surface.
170. Process of applying chlorine to the water before filtration is called

A. post-chlorination

B. pre-chlorination

C. double chlorination

D. break-point chlorination

Explanation: Pre-chlorination is the process of adding chlorine to raw water before it enters the filtration unit. This helps to reduce the bacterial load and algae, and assists in coagulation.
171. Which method of distribution can be adopted for cities which are situated at the foot-hills and the source of supply is available somewhere in the hills at sufficient elevation in relation to the elevation of the city?

A. Gravitational system

B. Pumping system

C. Combined gravity and pumping system

D. Pumping with storage system

Explanation: When the water source is located at a higher elevation than the city it supplies, water can be distributed using a gravitational system. This method uses the natural force of gravity to transport water, eliminating the need for pumps and reducing operational costs.
172. Choose the right matches among the following (1) Residual Chlorine (2) Suspended solid concentration (3) Hardness of water (4) Coagulant dose

A. 1 and 3 are correct

B. 1 and 2 are correct

C. 2 and 3 are correct

D. 3 and 4 are correct

Explanation: Orthotolidine Test is used to measure the residual chlorine in water. BOD (Biochemical Oxygen Demand) Test measures the amount of oxygen consumed by microorganisms to decompose organic matter, not suspended solids. EDTA (Ethylenediaminetetraacetic acid) titration is a common method for determining the hardness of water. MPN (Most Probable Number) is a method used for the bacteriological analysis of water to estimate the concentration of coliform bacteria, not coagulant dose. Therefore, the correct matches are 1 and 3.
173. In which system of water supply, water is supplied only during fixed hours of the day?

A. Gravity system

B. Pumping system

C. Continuous system

D. Intermittent system

Explanation: An intermittent system of water supply delivers water for a limited duration each day, not continuously. This system is often implemented in areas with water shortages.
174. To remove temporary hardness of water ______ is used.

A. $MgCl_{2}$

B. $CaCl_{2}$

C. $Ca(OH)_{2}$

D. $Mg(HCO_{3})_{2}$

Explanation: Temporary hardness in water, caused by carbonates and bicarbonates, can be removed by adding slaked lime, or Calcium Hydroxide ($Ca(OH)_{2}$), in a process known as the Lime-Soda process.
175. The most suitable formula for calculating the quantity of storm water for conditions prevailing in South India is

A. Dicken's formula

B. Ryve's formula

C. Inglis's formula

D. Fanning's formula

Explanation: Ryve's formula is an empirical formula for calculating the quantity of storm water runoff, and it is considered the most suitable for the conditions prevalent in South India.
176. The total storage capacity of a distribution reservoir is the summation of

A. Balancing storage and breakdown storage

B. Balancing storage and fire storage

C. Balancing storage, fire storage and breakdown storage

D. Breakdown storage and fire storage

Explanation: The total storage capacity of a distribution reservoir is the sum of three types of storage: balancing storage (to meet fluctuating demand), fire storage (for emergency fire-fighting needs), and breakdown storage (to cover for pump or power failures).
177. If $M=$ Area in $km^2$ and 'C' is a constant, Dicken's formula for calculating the quantity of storm water (Q) is

A. $Q=14~CM^{3/4}$

B. $Q=14~CM^{4/3}$

C. $Q=15~CM^{3/4}$

D. $Q=15~CM^{4/3}$

Explanation: Dicken's formula is an empirical formula used to calculate the peak flood discharge from a catchment area. It is given by $Q = CM^{3/4}$, where C is Dicken's constant. The specific coefficient of 14 is often used, thus the formula is $Q=14~CM^{3/4}$.
178. Which units involved in preliminary treatment of sewage for grinding or chopping large size suspended solids?

A. Grit chamber

B. Comminutors

C. Pumping

D. Skimming tanks

Explanation: Comminutors are mechanical devices used in the preliminary treatment of sewage to grind or chop large solids into smaller, more manageable particles before they enter subsequent treatment stages.
179. What are the structures that are constructed at suitable interval along the sewerage system to facilitate their operation, maintenance and inspection called?

A. Septic tanks

B. Sludge tanks

C. Sedimentation tanks

D. Sewer appurtenances

Explanation: Sewer appurtenances are structures built along a sewerage system at regular intervals to provide access for inspection, cleaning, and maintenance, such as manholes, drop manholes, and flushing tanks.
180. The sewage should be discharged deep into the sea, preferably, from which distance away from the shore

A. 1 to 1.5 km

B. 2 to 2.5 km

C. 3 to 3.5 km

D. 4 to 4.5 km

Explanation: For safe disposal of sewage into the sea, it should be discharged far enough from the shore to allow for adequate dilution and dispersion. A distance of 3 to 3.5 km is generally considered a safe minimum.
181. The ratio between length of the sewer and velocity of flow when running full is known as

A. Inlet time

B. Time of flow

C. Time of concentration

D. Time intensity

Explanation: The time of flow is defined as the time taken for sewage to travel from one point to another in a sewer. It is calculated by dividing the length of the sewer by the velocity of flow.
182. Collection materials used in packed scrubbers are

A. Broken stone and fibre glass

B. Paper

C. Waste cloth

D. Dust

Explanation: Packed scrubbers are air pollution control devices. They use a packing material to increase the surface area for the interaction of gas and liquid. Common packing materials include broken stone and fiberglass.
183. Fog refers to visible aerosols in which dispersed phase has size of particles ranger from

A. 0.6 to 0.1 µ

B. 1.0 to 40 µ

C. 40 to 50 µ

D. 0.01 to 0.05 µ

Explanation: Fog is a type of aerosol, which is a suspension of fine solid particles or liquid droplets in the air. The particle size of the dispersed phase in fog typically ranges from 1.0 to 40 µ.
184. Which of the following is a air pollution control equipment?

A. Electrostatic Precipitator

B. Stack

C. Blower

D. Trickling Filter

Explanation: An Electrostatic Precipitator is a device used to remove fine solid particles, such as dust and smoke, from a flowing gas using the force of an induced electrostatic charge. It is a key piece of equipment for controlling air pollution.
185. Which of the following is not a solid waste disposal method?

A. Land filling

B. Incineration

C. Composting

D. Vaccum floatation

Explanation: Landfilling, incineration, and composting are all common methods for the disposal and management of solid waste. Vacuum flotation is a process used in wastewater treatment, not for solid waste disposal.
186. Case of a rectangular section $d\times b$ is a rhombus whose diagonals are equal to

A. $\frac{d}{3}, \frac{b}{3}$

B. $\frac{d}{2}, \frac{b}{2}$

C. $d, b$

D. $\frac{d}{6}, \frac{b}{6}$

Explanation: The middle-third rule for a rectangular section states that to avoid tensile stress, the eccentric load must fall within a core, which is a rhombus with diagonals of $d/3$ and $b/3$.
187. According to Euler's column theory, the crippling load for a column of length 'l' hinged at both end is

A. $\frac{\pi^{2}EI}{l^{2}}$

B. $\frac{\pi^{2}EI}{4l^{2}}$

C. $\frac{4\pi^{2}EI}{l^{2}}$

D. $\frac{2\pi^{2}EI}{l^{2}}$

Explanation: According to Euler's formula for columns, the crippling load ($P_{cr}$) for a column with both ends hinged is given by the formula $P_{cr} = \frac{\pi^2EI}{L_{e}^2}$. For a column hinged at both ends, the effective length ($L_e$) is equal to the actual length ($l$). Therefore, $P_{cr} = \frac{\pi^2EI}{l^2}$.
188. The inclined member carrying compressive load is

A. Post

B. Beam

C. Strut

D. Column

Explanation: A strut is a structural member that is subjected to an axial compressive force. It can be oriented in any direction, including inclined, unlike a column which is typically vertical.
189. For no tension in the section, the eccentricity must not exceed. Where, k = Radius of gyration and d = depth of the section

A. $\frac{3k^{2}}{2d}$

B. $\frac{3k^{2}}{4d}$

C. $\frac{2k^{2}}{d}$

D. $\frac{2k^{2}}{d^{2}}$

190. Determine the maximum stress induced in the column having stress due to direct stress as $60~N/mm^{2}$ and bending stress as $100~N/mm^{2}$

A. $40~N/mm^{2}$

B. $60~N/mm^{2}$

C. $100~N/mm^{2}$

D. $160~N/mm^{2}$

Explanation: The maximum stress ($\sigma_{max}$) in a column subjected to both direct and bending stress is the sum of the direct stress ($\sigma_{d}$) and the bending stress ($\sigma_{b}$). Therefore, $\sigma_{max} = \sigma_{d} + \sigma_{b} = 60 + 100 = 160~N/mm^{2}$.
191. How much load a long column can carry with fixed ends compared to both ends hinged

A. 4 times

B. 8 times

C. 16 times

D. 2 times

Explanation: According to Euler's formula, the crippling load is inversely proportional to the square of the effective length. The effective length of a column with fixed ends is $L_{e} = l/2$. The effective length of a column with hinged ends is $L_{e} = l$. The ratio of the crippling loads is $P_{fixed}/P_{hinged} = (\frac{\pi^2EI}{(l/2)^2})/(\frac{\pi^2EI}{l^2}) = l^2/(l^2/4) = 4$. Thus, a column with fixed ends can carry 4 times the load of a column with hinged ends.
192. The effective length of a column with one end hinged and the other end free is

A. L

B. 2 L

C. 0.7 L

D. 0.5 L

Explanation: For a column with one end hinged and the other end free, the effective length ($L_e$) is taken as 2L, where L is the actual length of the column.
193. The carry-over factor in a prismatic member whose far-end is fixed is

A. 0

B. 1

C. 2

D. 0.5

Explanation: In moment distribution method, the carry-over factor is the ratio of the moment at the far end to the moment applied at the near end. For a prismatic member with the far end fixed, the carry-over factor is 0.5.
194. A propped cantilever of span L' is subjected to a moment '+M' (sagging) at the propped end, the Fixed End Moment (FEM) at the fixed end will be

A. M

B. - M

C. $\frac{-M}{2}$

D. $\frac{M}{2}$

Explanation: For a propped cantilever, if a moment $M_B$ is applied at the propped end B, a moment of $M_A = M_B / 2$ is carried over to the fixed end A. If the moment is positive (sagging), the carried-over moment is also positive. So, the FEM at the fixed end will be $M/2$.
195. What is the degree of indeterminacy of the following fixed beam with inclined load?

A. 1

B. 2

C. 3

D. 0

Explanation: The degree of static indeterminacy ($D_s$) for a beam is given by $D_s = R - 3$, where R is the number of unknown reactions and 3 is the number of equilibrium equations. For a fixed beam, there are 3 reactions at each end (one vertical, one horizontal, and one moment), so R = 6. Thus, $D_s = 6 - 3 = 3$. The inclined load can be resolved into vertical and horizontal components, but this does not change the number of unknown reactions. Therefore, the degree of indeterminacy is 3.
196. Degree of indeterminacy of a propped cantilever is

A. 0

B. 1

C. 2

D. 3

Explanation: A cantilever beam is statically determinate. A propped cantilever has one extra support (the prop) compared to a simple cantilever, which provides one additional vertical reaction. Therefore, the degree of static indeterminacy is 1.
197. The deflection at the centre of a simply supported beam carrying a point load at the centre is given by

A. $\frac{WL^{2}}{48EI}$

B. $\frac{WL^{3}}{48EI}$

C. $\frac{WL^{2}}{24EI}$

D. $\frac{WL^{3}}{24EI}$

Explanation: The maximum deflection for a simply supported beam with a central point load is given by the formula $\delta_{max} = \frac{WL^3}{48EI}$, where W is the point load, L is the span, E is the Young's modulus, and I is the moment of inertia.
198. Rankine's formula is applicable for

A. Only short column

B. Only long column

C. Both short and long column

D. Only intermediate column

Explanation: Rankine's formula (or the Rankine-Gordon formula) is an empirical formula that is a hybrid of Euler's formula and a formula for short columns. It is designed to be applicable to columns of all lengths: short, intermediate, and long.
199. In the cantilever beam, deflection at point 'B' is

A. $\frac{Wl^{3}}{8EI}$

B. $\frac{Wl^{3}}{3EI}$

C. $\frac{Wl^{2}}{8EI}$

D. $\frac{Wl^{2}}{3EI}$

Explanation: For a cantilever beam with a point load 'W' at the free end, the deflection at the free end (point B) is given by the formula $\delta_B = \frac{WL^3}{3EI}$, where L is the length of the beam.
200. In simply supported beam with a uniformly distributed load, throughout the span the maximum deflection occurs at

A. One third of the span

B. At the supports

C. At mid span

D. At quarter span

Explanation: For a simply supported beam subjected to a uniformly distributed load (UDL) over its entire span, the bending moment is maximum at the center, and the deflection is also maximum at the mid-span.

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